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14=5x^2-33x
We move all terms to the left:
14-(5x^2-33x)=0
We get rid of parentheses
-5x^2+33x+14=0
a = -5; b = 33; c = +14;
Δ = b2-4ac
Δ = 332-4·(-5)·14
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-37}{2*-5}=\frac{-70}{-10} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+37}{2*-5}=\frac{4}{-10} =-2/5 $
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